A point rotates about the origin in the xy plane at a constant radius of 0.210 m

Question

A point rotates about the origin in the xy plane at a constant radius of 0.210 m and angular velocity of 8.28 rad/s. As you know, the projections of this point on the x- and y-axes undergo simple harmonic motion. What is the amplitude of this motion? Whats is the Frequency(Hz)? What is the Period (s)? Show Work Please!!! I need to be able to work it myself!
A point rotates about the origin in the xy plane at a constant radius of 0.210 m and angular velocity of 8.28 rad/s. As you know, the projections of this point on the x- and y-axes undergo simple harmonic motion. What is the amplitude of this motion? Whats is the Frequency(Hz)? What is the Period (s)? Show Work Please!!! I need to be able to work it myself!
A point rotates about the origin in the xy plane at a constant radius of 0.210 m and angular velocity of 8.28 rad/s. As you know, the projections of this point on the x- and y-axes undergo simple harmonic motion. What is the amplitude of this motion? Whats is the Frequency(Hz)? What is the Period (s)? Show Work Please!!! I need to be able to work it myself!

Explanation / Answer

amplitude = radius= 0.210m
frequency, f= angular velocity/ 2pi=1.318Hz
time period= 1/f=0.7587 sec   

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