A closely wound, circular coil with radius 2.7 cm has 850 turns...At what distan

Question

A closely wound, circular coil with radius 2.7 cm has 850 turns...At what distance x from the center of the coil, on the axis of the coil, is the magnetic field half its value at the center...(Magnetic Field at Center = 5.3X10^-2) ( Current = I = 2.68 A) A closely wound, circular coil with radius 2.7 cm has 850 turns...At what distance x from the center of the coil, on the axis of the coil, is the magnetic field half its value at the center...(Magnetic Field at Center = 5.3X10^-2) ( Current = I = 2.68 A)

Explanation / Answer

2) the magnetic field at a distance say x fromthe center of the coil on the axis of the coil is                  B =?0Ia2/2(a2+x2)3/2     so we have       ?0Ia2/2(a2+x2)3/2= 1/2*( ?oNI / 2a)
   simplyfying we we get      22/3a3 =x2+a2        calculate for x
2^2/3 * (0.027)^2 = x^2 +(0.027) ^2
x= 0.02069 m

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