Consider the R-L low pass filter circuit described in the introduction. As the f

Question

Consider the R-L low pass filter circuit described in the introduction. As the frequency is increased the amplitude of the voltage across the resistor gradually changes from its maximum V to zero. At what frequency f will the amplitude of the voltage across the resistor be 1/square root 2 of its maximum value V? Evaluate this frequency numerically for the case of R = 1k ? and L=65 mH. Consider the R-L low pass filter circuit described in the introduction. As the frequency is increased the amplitude of the voltage across the resistor gradually changes from its maximum V to zero. At what frequency f will the amplitude of the voltage across the resistor be 1/square root 2 of its maximum value V? Evaluate this frequency numerically for the case of R = 1k ? and L=65 mH.

Explanation / Answer

Vo/Vi = R/sqrt(R^2 + (wL)^2) = 1/sqrt(2) => w =R/L =1000/0.065 = 15384.62 => f = w/2pi = 2449.78 Hz

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