When two lenses are used in combination, the first one forms an image that then

Question

When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.40 -tall object is 60.0 to the left of a converging lens of focal length 40.0 . A second converging lens, this one having a focal length of 60.0 , is located 300 to the right of the first lens along the same optic axis. (Units are in cm)

Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.

Thanks.

Explanation / Answer

for first lens 1/v+1/u = 1/f [ u = 60 , f = 40] => v = 120 For second lens u = 300-120 = 180 1/180+1/v =1/60 v = 90 location of image produced by second lens = 90 to the right of it m1 = -2 , m2 = -1/2 net magnification = 1 Height of final image = 1.4

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