A negative charge (–q) traveling from left to right across the page (+x direct

Question

A negative charge (–q) traveling from left to right across the page (+x direction, speed v) crosses (at x = 0) from a region of zero magnetic field to a region uniform non-zero field B pointing into the page (–z direction). The charge is observed to exit the field in the opposite direction from which it came. Draw a picture of the charge’s trajectory in the x-y plane of the page. (Indicate the region of non-zero field with “xâ€s.) If the separation between the incoming and return paths is d, what is the mass of the charge in terms of q, B, d, and v?

Explanation / Answer

The formula that applies in this case is r = mv/qB

r, the radius, is d/2, so

d/2 = mv/qB

Solving this for m gives us

m = qBd/2v

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