pleasd explain The figure below shows a particle of mass m = 2.0 kg and charge q
ID: 2104932 • Letter: P
Question
pleasd explain
The figure below shows a particle of mass m = 2.0 kg and charge q = +50 /mu C that is attached to a pivot point by a nonconducting string. To the right of this particle is an infinite non-conducting vertical plane having a charge per area of sigma = -8 /mu C/m2, as shown in the following figure. If the charge hangs in equilibrium, determine the angle theta that the string makes with the negative vertical. Assume that g = 9.8 m/s2 and that gravity acts downward in the figure. 25.6degree 33.3degree 49.1degree 53.4degree 66.6degree None of the above.Explanation / Answer
from free body diagram
qE = Tsin(theta)
mg = T cos(theta)
tan (theta) = qE/mg
q = 50 x 10^-6 C
E = sigma/2e = (8 x 10^-6) / (2x 8.854 x 10^-12)
mass m = 2kg
solving we get theta = 49.1 degrees
answer is C) 49.1 degrees
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