A 15,000 kg loader traveling east at 20 km/h turns south and travels at 25 km/h.

Q: A 15,000 kg loader traveling east at 20 km/h turns south and travels at 25 km/h.

final Velocity in m/s 25*518 = 9.944 Initial Velocity in m/s 20*/18 = 5.55 K.E. = 1/2m(v2^2 - v1^2) = 13020.83 J linear momentum = m(v2 - v1) v2 = -9.944j v1 = 5.55i Hence change in P = mv2 - mv1 = -83250 i - 149160j b.) using conservation of momentum as there is no momentum in the x direction m1v1 -m2v2 = 0 v2 = 150*20/(470-150) = 9.375 m/s

ID: 2104941 • Letter: A

Question

A 15,000 kg loader traveling east at 20 km/h turns south and travels at 25 km/h. Calculate the change in the loaderâ€™s

kinetic energy.
linear momentum.

A 470-g firework is traveling straight up at 13 m/s when it explodes into two pieces. The smaller piece (150 g) shoots off horizontally towards the East at 20 m/s. Find the speed and direction of the other piece directly after the explosion. A 470-g firework is traveling straight up at 13 m/s when it explodes into two pieces. The smaller piece (150 g) shoots off horizontally towards the East at 20 m/s. Find the speed and direction of the other piece directly after the explosion.

Explanation / Answer

final Velocity in m/s 25*518 = 9.944

Initial Velocity in m/s 20*/18 = 5.55

K.E. = 1/2m(v2^2 - v1^2) = 13020.83 J

linear momentum = m(v2 - v1)

v2 = -9.944j

v1 = 5.55i

Hence change in P = mv2 - mv1 = -83250 i - 149160j

b.) using conservation of momentum
as there is no momentum in the x direction

m1v1 -m2v2 = 0
v2 = 150*20/(470-150) = 9.375 m/s

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A 15,000 kg loader traveling east at 20 km/h turns south and travels at 25 km/h.

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