A block with mass m = 6.9 kg is attached to two springs with spring constants k

Question

A block with mass m = 6.9 kg is attached to two springs with spring constants kleft = 36 N/m and kright = 57 N/m. The block is pulled a distance x = 0.2 m to the left of its equilibrium position and released from rest.

7)

Where is the block located, relative to equilibrium, at a time 1.15 s after it is released? (if the block is left of equilibrium give the answer as a negative value; if the block is right of equilibrium give the answer as a positive value)

8)

What is the net force on the block at this time 1.15 s? (a negative force is to the left; a positive force is to the right)

9)

What is the total energy stored in the system?

10)

Explanation / Answer

7) net force = (36*0.2)+(57*0.2) = 18.6 N

towards right side

8)equaton of motion =

x= 0.2 sin(pie*0.5 + 3.67t)

position at t = 1.15

x = 0.0201 m

9) total energy = (0.5*36*0.2*0.2)+(0.5*57*0.2*0.2) = 1.86 J

10)

T = 2*pie (m/k1+k2)^0.5

time period wouldnotchange

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