A solid sphere with a radius of 9.3 cm an mass of 373 g is allowed to roll 4.30

Question

A solid sphere with a radius of 9.3 cm an mass of 373 g is allowed to roll 4.30 m without slipping down a 13.2 degree incline.
a. What is the moment of inertia of the sphere?
b. By how much does the gravitational potential energy of the sphere change?
c. If the sphere started at rest, what is the speed of the center of mass of the sphere at the end? A solid sphere with a radius of 9.3 cm an mass of 373 g is allowed to roll 4.30 m without slipping down a 13.2 degree incline.
a. What is the moment of inertia of the sphere?
b. By how much does the gravitational potential energy of the sphere change?
c. If the sphere started at rest, what is the speed of the center of mass of the sphere at the end?

Explanation / Answer

moment of inertia = 2mr^2/5 = 1.29 x 10^-3 kg-m^2 b) change in gravitational PE = mgh =0.373 x 9.8 x 4.30sin13.2 = 3.589 J c) v =(2gh)^0.5 = (2x9.8x4.3xsin13.2)^0.5=4.386 m/s

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