How much charge from battery to capacitor?

Question

Consider a 3.2-pF parallel-plate capacitor that just has air between its plates. Let it be connected to a 5.7-V battery. Now, a piece of electrical insulator with dielectric constant 7 is inserted between the plates. How many micro-coulombs of charge, Q, flows from the battery to the capacitor (and from the capacitor to the battery), as the insulator is inserted? Consider a 3.2-pF parallel-plate capacitor that just has air between its plates. Let it be connected to a 5.7-V battery. Now, a piece of electrical insulator with dielectric constant 7 is inserted between the plates. How many micro-coulombs of charge, Q, flows from the battery to the capacitor (and from the capacitor to the battery), as the insulator is inserted?

Explanation / Answer

Q = CV

Q = 3.2*10^-12 * 5.7

Q = 18.24 pC

as a result of placing an insulator

C' = 7C

Q' = 7Q = 127.68 pC

the charge that flows = 109.44pico C

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