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Will rate super high!!! The figure shows the pV diagram for a certain thermodyna

ID: 2108548 • Letter: W

Question

Will rate super high!!!


The figure shows the pV diagram for a certain thermodynamic process. In this process, 1940 J of heat flows into a system, and at the same time the system expands against a constant external pressure of 7 Times 104 Pa. If the volume of the system increases from 0.020 m3 to 6 Times 10-2 m3, calculate the change in internal (thermal) energy of the system. If the internal (thermal) energy change is nonzero, be sure to indicate whether this energy change is positive or negative.

Explanation / Answer

1940=7*10^4*0.04+change in U

so change in U=-860J


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