Hi, I\'m close (I think) but not coming up with the correct answer. At low speed

Question

Hi, I'm close (I think) but not coming up with the correct answer.

At low speeds, a charged object in a magnetic field moves in a circular path of radius r = mv/qB. If an electron moves in an orbit of radius 10 cm with a speed of 1.0 x 10^5 m/s, what will the radius be when its speed is 0.96c? Thesqrt answer is 0.124 nm, and that isn't what I've come up with.

I solved r = mv/qB to find B = 1.456 x 10 ^-43, then tried to resolve for r with the new radius. That wasn't right, plus it didn't take into account any relativistic effect. The equation from this part of the chapter is

m = mo/ sqrt 1 - v^2/C^2. but I'm not sure where to apply it. Thanks!

Okay, a poster suggested using the mass formula and reworking the formula. I ended up with m = 4.55x10^-30 kg. When inserting it back into the radius formula, I came up with 5.65x10^38, not the right answer still.

Explanation / Answer

10 = m0*10^5*k

x=m0/0.28*0.96*3*10^8*k

on divinding both we get

x = 1028.57 m

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