A barbell spins around a pivot at its center at A. The barbell consists of two s

Question

A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 450 grams (0.45 kg), at the ends of a very low mass rod of length d = 35 cm (0.35 m; the radius of rotation is 0.175 m). The barbell spins clockwise with angular speed 120 radians/s.


(e) Calculate the translational kinetic energy of ball 1.


(f) Calculate the translational kinetic energy of ball 2.


(g) By adding the translational kinetic energy of ball 1 and the translational kinetic energy of ball 2, calculate the total kinetic energy of the barbell.

Explanation / Answer

translational kinetic energy = (1/2)mv2

translational kinetic energy of ball 1 and ball 2 are same = 0.5*0.45*((0.175*120)^2) =99.225 kg.m2s-2

Total kinetic energy of the bareball = 198.45 kg.m2s-2

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