Consider the following circuit with a 5 Volt battery and 100 %u03A9 resistor: 1

Question

Consider the following circuit with a 5 Volt battery and 100 %u03A9 resistor:

1What is the relationship between electric potential and electric potential energy?

2.How much electric potential energy does each electron lose when passing through the resistor?

Now consider light of frequency (f), wavelength ( %u03BB) and velocity of light (c).

3. What is the relationship between f and %u03BB?

4.What is the relationship between the energy of a photon (E) and frequency of its light (f)?

5. Calculate the energy of a photon of wavelength 500 nm. (1nm = 10-9m)

6. If electrons flowing in a circuit were to lose an amount of energy equal to the photon energy found in the last question, what would be their change in voltage?

Explanation / Answer

1. Electric Potential energy = Charge * electric potential

2. Electric potential energy lost = 5*1.6*10^-19 = 8*10^-19 J

3.c=f*wavelength

4. E=h*f

5.E =Hc/Lambda = 3.984*10^-19 J

6.V = 3.984*10^-19/1.6*10^-19 =2.49 V

Change in voltage = 2.49 V

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