A gas is in a sealed container. The gas pressure is tripled and the temperature

Question

A gas is in a sealed container. The gas pressure is tripled and the temperature is doubled. What happens to the number of moles of gas in the container?         What happens to the number density of the gas in the container?        I know the answer deals with PV=NRT, I am just not sure how to apply it, thanks for your help! A gas is in a sealed container. The gas pressure is tripled and the temperature is doubled. What happens to the number of moles of gas in the container?         What happens to the number density of the gas in the container?        I know the answer deals with PV=NRT, I am just not sure how to apply it, thanks for your help! A gas is in a sealed container. The gas pressure is tripled and the temperature is doubled. What happens to the number of moles of gas in the container?         What happens to the number density of the gas in the container?        I know the answer deals with PV=NRT, I am just not sure how to apply it, thanks for your help!

Explanation / Answer

p1v1=n1RT1 ................(1)

3p1*v1=n2*R*2T1 ................(2)

DIVIDING BOTH WE GET

3=2*n2/n1

n2=1.5n1

now

P1*M=(rho1)*R*T1

3P1*M=(rho2)*R*2T2

DIVIDING WE GET

rho2=1.5rho1

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