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1) A 500 kg mass is released at rest from a distance of two Earth radii above th

ID: 2113127 • Letter: 1

Question

1) A 500 kg mass is released at rest from a distance of two Earth radii above the surface of the Earth. Find the speed of the mass when it has fallen to a distance of one radius above the surface of the Earth.


2) If the mass of Jupiter is 1.8 x 10^27 kg and its radius is 7.1 x 10^7 m, then find the escape velocity for an object launched from the surface of Jupiter.


3) A person pushes with a force of 10.0 N on a stick pin to try to push it into a bulletin board. If the tip of the needle is a circle with a radius of 0.12 mm, then what is the average pressure (in Pascals) on the board at the tip of the pin?


4) An object has a volume of 0.25 m^3 and weighs 3000 N. What will be its apparent weight when submerged in water?


5) A plastic block of dimensions 2.5 cm x 3.8 cm x 4.0 cm has a mass of 28.0 g. What is the density of the block? If placed into a cup of water, will the block float or sink?


6) A concrete block of dimensions 1.00 m x 2.50 m x 2.75 m has what weight in Newtons? Use 2400 kg/m^3 as the density of concrete.


7) A 13000 N vehile is to be lifted by a 25 cm diameter hydraulic piston. What force needs to be applied to a 3.5 cm diameter piston to accomplish this?


8) A perfect fluid flows through a pipe with varying radius. If at one cross section with radius 20 cm the fluid is flowing at 5.0 m/s, then what is the speed at a cross section with radius 4.0 cm?

Explanation / Answer

please rate me 1)From conservation of energy Initial PE = Gmm/r Then after the partial fall, it will have PE and KE Since energy is conserved, GMm/r^2 = GMm/r'^2 + .5mv^2 (m cancels) (6.67 X 10^-11)(5.98 X 10^24)/(3)(6.38 X 10^6) = (6.67 X 10^-11)(5.98 X 10^24)/(2)(6.38 X 10^6) + (.5)(v^2) v = 4565 m/s