1) A 50kg crate is pulled 40m along a horizontal floor by a constant force exert
ID: 1283343 • Letter: 1
Question
1) A 50kg crate is pulled 40m along a horizontal floor by a constant force exerted by a person Fp= lOON, which acts at a 37o angle as in the picture below. 1f the velocity is constant, determine the work donc by a) force of the person pulling. b) The gravitational force exerted by earth. e) The normal force. d) The frictional force e) Calculate the total work. Show your work. f) The pulling force is increased to 150 N. Find the acceleration of the box. g) Find the work done by each force below a. Gravitational force exerted by earth b. Normal force e. Frictional force d. Pulling force e. Calculate the total work doneExplanation / Answer
a) W = Fdcos37 = 100x 40 x cos37 = 3194.54 J
b) gravitaional is perpendicular to displacement .
@= 90 degrees .
W= zer0 .
c) normal force is also perpendicular.
W = Zer0 .
d) friction force = 100cos37 =79.86 N
W = F.d cos180 = - 79.86 x 40 = -3194.54 J
e) total work done = sum of all forces listed above = 0
f) Fcos37 - f = ma
150cos37 - 79.86 = 50a
a = 0.80 m/s2
g) a. W = 0
b. W =0
C. W = - 79.86 x 40 = -3194.54 J
d. W = 150 x 40 x cos37 = 4791.81 J
e) Wtotal = 0 + 0 + (-3194.54 ) + 4791.81 = 1597.27 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.