pleasae show all steps, equations, and work for problem, not a wolframalpha answ
ID: 2113979 • Letter: P
Question
pleasae show all steps, equations, and work for problem,
not a wolframalpha answer
Two billiard balls of equal mass (m=l kg) approach each other along the x-axis; one is moving to the right with a speed of v1=10 m/s and the other is moving to the left with a speed of v2=5 m/s. After the collision, which is elastic, one of the balls moves in the direction of the y-axis theta=54.73 degree What is the initial linear momentum of the two-ball system? What is the initial kinetic energy of the two-ball system? What are the speeds of ball 1 and ball 2 after the collision?Explanation / Answer
1) linear momentum = 1(10-5) =5
2) K.E = .5 (100+25) =62.5 J
3) since there is no vertical momentu
V3 = V4sin54.73
v3 = .81v4
and in horizontal direction
v4 cos54.73 = 5
v4=8.65
V3=7.01
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.