.1 An object 2.00 cm high is placed 43.5 cm to the left of a converging lens hav

Question

.1

An object 2.00 cm high is placed 43.5 cm to the left of a converging lens having a focal length of 32 cm. A diverging lens with a focal length of -20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) Determine the position of the final image. image distance 24.4 cm image location to the right of the diverging lens Determine the magnification of the final image. -0.561 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. x Is the image upright or inverted? inverted Repeat parts (a) and (b) for the case where the second lens is a converging lens with a focal length of +20.0 cm. image distance cm image location to the right of the second lens magnification x image orientation inverted

Explanation / Answer

I see you are only looking for the magnification, all of your other answers are right...

Here is what you need

For the first lens

1/f = 1/p + 1/q

1/32 = 1/43.5 + 1/q

q = 121 cm

For the second lens

1/-20 = 1/-11 + 1/q

q = 24.4 cm

That is what you got for the final image location. Now use those for the magnification

M = -q/p times -q/p

M = -121/43.5 times -(24.4)/(-11)

M = -6.17

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