Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

1. Student observed ten antinodes on a string of length 1.70 m under tension pro

ID: 2115074 • Letter: 1

Question

1. Student observed ten antinodes on a string of length 1.70 m under tension produced by a mass of 0.22 kg. The string linear density is 1.3 gram/meter. What is the difference between the transverse wave velocity calculated from the string material properties and the one following from the standing wave configuration?



1*. The experimental strings are not ideally rigid, and have some elasticity: the stronger the pull, the bigger the elongation. What is the effect on the transverse wave velocity as compared to the transverse wave velocity in an ideal string?


2. At room temperature (20 deg. Celsius) there is a low rate sublimation of iodine molecules. Compare their average velocity after leaving the solid with that at the temperature of the experiment of diffusion of iodine.



2*. A student weighed a chunk of solid CO2 as 1.82 gram. What is the gas-to-solid volume ratio if the sublimated chunk produced gaseous carbon dioxide with volume 0.85 liter at atmospheric pressure. The additional necessary datum is given in the text (Analysis).

Explanation / Answer

velocity of wave = sqrt ( tension / linear mass density )


tension = 0.22 * 9.8 = 2.156 T


so velocity = sqrt ( 2.156 / 1.3*10^-3 ) = 40.7242 m/sec

This is the velocity according to material properties


1)

The distance between antinode is given by : L / n = wavelength / 2


so wavelength = 2 * L / n

where L = length of string

n = number of antinodes


now velocity = wavelength * frequesncy

so velcoty is proportional to length ..


as in elastic spring.. the length will increase.. so the velcity will increase


2)