I need 021. A simple pendulum consists of a ball of mass 5.04 kg hanging from a

Question

I need 021.

A simple pendulum consists of a ball of mass 5.04 kg hanging from a uniform string of mass 0.0737 g and length L. The period of oscillation for the pendulum is 1.42 s. Determine the speed of a transverse wave in the string when the pendulum is stationary and hangs vertically. The acceleration of gravity is 9.8 m/s2. Answer in units of m/s A standing wave of frequency 5 hertz is set up on a string 2 meters long with nodes at both ends and in the center. 1 Hz 2.5 Hz A stretched string is fixed at b are 550 cm apart. If the density of the string i and its tension is 600 N, wha length of the 5th harmonic? Answer in units of cm The figure below represent a w with both ends held in fixed p

Explanation / Answer

we have when it is stationary tension in the string = mg =5.04*9.8 =49.4 N and mass per unit length of sting= mass/ length we have T= 2*pi*root (l/g) so L= T^2*g/4*pi^2 so L= (1.42)^2*9.8/4*pi^2 =0.5 m so mass per unit length= 0.0737*10^-3/0.5 =0.1474*10^-3 Kg/m so v= root (T/u) = 578.9 m/s

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