A student performs a ballistic pendulum experiment using an apparatus. Initially

Question

A student performs a ballistic pendulum experiment using an apparatus. Initially the bullet is fired at the block while the block is at rest (at its lowest swing point). After the bullet hits the block, the block rises to its highest position, and continues swinging back and forth. The following data is obtained: the maximum height the pendulum rises is 2 cm, at the maximum height the pendulum subtends an angle of 29.9 degrees , the mass of the bullet is 65 g, and the mass of the pendulum bob is 811 g Determine the initial speed of the projectile. The acceleration due to gravity is 9.8 m/s2 . Answer in units of m/s A student performs a ballistic pendulum experiment using an apparatus. Initially the bullet is fired at the block while the block is at rest (at its lowest swing point). After the bullet hits the block, the block rises to its highest position, and continues swinging back and forth. The following data is obtained: the maximum height the pendulum rises is 2 cm, at the maximum height the pendulum subtends an angle of 29.9 degrees , the mass of the bullet is 65 g, and the mass of the pendulum bob is 811 g Determine the initial speed of the projectile. The acceleration due to gravity is 9.8 m/s2 . Answer in units of m/s Determine the initial speed of the projectile. The acceleration due to gravity is 9.8 m/s2 . Answer in units of m/s

Explanation / Answer

Initial momentum of the block and bullet = 65*u +0
After collision the final momentum of both = (811 +65)*v

65*u= (876)*v
u= 13.4769 v
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Using v^2 = 2gh, v = %u221A (19.6 * 0 .05) = 0.99 m/s
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u= 13.476* 0.99 = 13.34m/s

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