A student performs a bomb calorimetry experiment with benzoic acid. In this expe

Question

A student performs a bomb calorimetry experiment with benzoic acid. In this experiment she combusts 1.0039 g benzoic acid and observes a total temperature increase of +2.61?C. The mass of fuse?wire burned in the reaction was 0.0125 g and the total mass of water that she placed in the calorimeter bucket was 2000.8 g. Calculate the heat capacity of the bomb (Cbomb) given that under constant volume conditions the specific heat of combustion of benzoic acid is 26,434 J.g?1.

Would the fuse-wire be considered as a nichrome fuse wire in this question then the Cwire would be 5857.6 J/g right?

So would the solution be considered be

(Cbomb) = (Cbenz*mass of benz+Cwire*mass of wire)/change in temp?

thank you for your help!

Explanation / Answer

The combustion of sample (benzoic acid) inside the bomb delta Hc = delta Hc (benzoic acid) x m (benzoic acid) + delta Hc (Ni fuse wire) x delta m (Ni fuse wire)

delta Hc = Cv. delta T
Cv = delta Hc /delta T

(Nickel fuse wire ) heat of combustion = 981.3 cal/g =4105.76 J/g

Cv = [26434 x 1.0039 + 4105.76 x 0.0125 ] / 2.61 =10187.132 J / C

delta show the change in the quantity.

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