Water is placed in the container shown. It is open to the atmosphere at the top.

Question

Water is placed in the container shown. It is open to the atmosphere at the top. The diameter %u21131 = 0.3 m, diameter %u21132 = 0.07 m,

and height is 0.47 m

What is the gauge pressure at point A when spigot C is closed. The density of water is %u03C1 = 1 g/cm3 and g = 9.8 m/s^2. Atmospheric pressure is 10100 N/m^2. The acceleration of gravity is 9.8 m/s$2.

Answer in units of N/m2

What is the absolute pressure at point B whenspigot C is closed?

Answer in units of N/m^2

Spigot C is opened. What is the velocity of water upon leaving the spigot? Neglect the slow drop in height of water in the container. The %uFB01gure is misleading; assume C is at the same level as A and B.

Answer in units of m/s

After the water has fallen through an additional height h2 = 0.8 m, what is its new velocity?

Answer in units of m/s

Please provide an in depth explination. I need to be able to understand and reproduce the work!

Explanation / Answer

a.)9.8*1000*0.47=4606 N/m^2

b.)10100+4606=14706 N/m^2

c.)4606=0.5*1000*v^2

So v=3.03513 m/s

d.)4606 + 1000*9.8*0.8=0.5*1000*v^2

12446=0.5*1000*v^2

So v=4.98918 m/s

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