Can\'t get the integrals right, please help. A closed surface with dimensions a

Question

Can't get the integrals right, please help.

A closed surface with dimensions a = b = 0.400 m and c = 0.700 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is nonuniform and given by Erightarrow = (4.80 + 1.20x2)ihat N/C, where x is in meters. Find the absolute value of the amount of electric flux which is entering the surface. (Consider only those locations where the electric flux is entering the surface). N · m2/C Find the absolute value of the amount of electric flux which is exiting the surface. (Consider only those locations where the electric flux is exiting the surface). N · m2/C Calculate the net electric flux leaving the closed surface. The correct answer is not zero. N · m2/C What net charge is enclosed by the surface? C

Explanation / Answer

Electric flux at left surface which is located at x=a

a)

Phi=-E*A=-(4.8+1.2*0.4^2)*0.4*0.4=-0.79872 N.m^2/c

Electric flux at left surface which is located at x=a+c

b)

Phi=E*A=(4.8+1.2*1.1^2)*0.4*0.4=1.00032 N.m^2/c

c)

phi=1.00032+0.79872=1.79904 N.m^2/c

d)

q = %u222E %u0112 %u22C5 d%u0100 =0

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