Find E and E infinity A ring of charge is centered at the origin in the vertical

Question

Find E and E infinity

A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of lambda = 5.46 times 10-6 C/m and a radius of R = 2.01 cm. Find the total electric field, E, of the ring at the point P = (1.10 m, 0.00 m). The Coulomb force constant is k = 1/(4pi epsilon0) = 8.99 times 109 Nm2/C2. E = Find the expression for the electric field, infinity, of the ring as the point P becomes very far from the ring (x >> R) in terms of the radius R, the distance x, the total charge on the ring q, and the constant k = 1/(4pi epsilon0). infinity =

Explanation / Answer

EF due to a ring of radius R ad distance x => E = Kqx/(x^2+R^2)^1.5

A) E = 56748.24 N/m

B) at x>>R => E = Kq/x^2

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