A submarine dives to a depth of 286 feet in the ocean. What is the force (in pou

Question

A submarine dives to a depth of 286 feet in the ocean. What is the force (in pounds) acting on a hatch that has an area of 2.9 square feet? WARNING: do not use the information associated with Figure 4.26 to solve this problem because the round off error will cause you to get the wrong answer. Do not consider atmospheric pressure in your calculation, since the pressure inside of the submarine is maintained at 1 atmosphere, which offsets the 1 atmosphere of pressure that normally would be added to the gauge pressure. A submarine dives to a depth of 286 feet in the ocean. What is the force (in pounds) acting on a hatch that has an area of 2.9 square feet? WARNING: do not use the information associated with Figure 4.26 to solve this problem because the round off error will cause you to get the wrong answer. Do not consider atmospheric pressure in your calculation, since the pressure inside of the submarine is maintained at 1 atmosphere, which offsets the 1 atmosphere of pressure that normally would be added to the gauge pressure. A submarine dives to a depth of 286 feet in the ocean. What is the force (in pounds) acting on a hatch that has an area of 2.9 square feet? WARNING: do not use the information associated with Figure 4.26 to solve this problem because the round off error will cause you to get the wrong answer. Do not consider atmospheric pressure in your calculation, since the pressure inside of the submarine is maintained at 1 atmosphere, which offsets the 1 atmosphere of pressure that normally would be added to the gauge pressure.

Explanation / Answer

Given that the depth is h=286 ft                                         =87.1728 m density od sea water is p=1025 kg/m3 the pressure at this depth is P=Po+pgh                                               =1.013 x 105+(1025)(9.8)(87.125)                                              
                                               =976470.625Pa area A=2.9ft2            0.2694188264301727 m2 then the force exerted is F=PA                                          =263079.5698310372 N then the force exerted is F=PA                                          =263079.5698310372 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.