Two long, straight wires are oriented perpendicular to the page, as shown in the

Question

Two long, straight wires are oriented perpendicular to the page, as shown in the figure(Figure 1) . The current in one wire is I1=3.0A, pointing into the page, and the current in the other wire is I2=4.0A, pointing out of the page.

Part A: Find the magnitude and direction of the net magnetic field at point P.

Must be in 2 sig figs and in %u03BCT

Part B:   

%u03B8 %u2218angle below the dashed line to the right P

I am looking the just the correct answer, first person to have both correct will recieve 5 stars.

Thank you for all the help

Explanation / Answer

r1=5cm ,r2=sqrt(5^2+5^2)=7.1 cm

theta =cos^-1(r1/r2) =cos^1-(5/7.1)=45 degrees

B1=uoI/2pir1 =(4pi*10^-7)*3/2pi*0.05

B1=1.2*10^-5 T

B2=uoI2/2pir2 =(4pi*10^-7)*4/2pi*0.071

B=1.13*10^-5 T

B1x =B1 =1.2*10^-5 T

B2x= -B2cos(theta) =-1.13*10^-5*cos45

B2x=-8*10^-6 T

Bx=B1x-B2x =1.2*10^-5-8*10^-6

Bx=4*10^-6 T

B1y=0

B2y=-B2sin(thete)=-1.13*10^-5*sin45=-8*10^-6 T

By =B1y+B2y=-8*10^-6 T

a)

B=sqrt(Bx^2+By^2] =sqrt[4*10^-6)^2+(-8*10^-6)^2]

B=8.94*10^-6 T

b)

angle =tan^-1(BY/Bx) =tan^-1(-8/4)

angle =63.43 degrees

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