A cannon on a cliff at a height of H = 35 meters fires a cannonball in the horiz

Question

A cannon on a cliff at a height of H = 35 meters fires a cannonball in the horizontal direction.
The initial velocity of the cannonball is 6.9 m/s.
What is the horizontal distance D which the cannonball travels before it hits the ground below?

What will the speed of the ball be just before it hits the ground?

What direction will the cannonball be moving just before it hits the ground?
Enter the angle relative to the horizontal axis.
(Hint: the angle should be negative and the units should be deg.

Explanation / Answer

H = 1/2 *g*t^2

t = 2.67 sec

X = ut = 6.9*2.67 = 18.44 m

Vy = Uy + gt

Vy = 9.8 * 2.67 = 26.17 m/s downward direction

Vx = 6.9 m/s

Theta = Tan^-1(26.17/6.9) = 75.23 Deg

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