The diagram depicts an RC-circuit where C = 7.60 F, R0 = 24.5 , R1 = 13.5 , R2 =

Question

The diagram depicts an RC-circuit where C = 7.60 F, R0 = 24.5 , R1 = 13.5 , R2 = 24.5 and V = 2.00 Volts. The capacitor is initially uncharged.

1)What is the current through R1 immediately after the switch S is closed?

2)What is the current through R2 immediately after the switch S is closed?

3) What is the current through the capacitor immediately after the switch S is closed?

4) What is the current through R1 after the switch S has been closed for a very long time? Assume that the battery does not go dead.

PLEASE EXPLAIN HOW TO SOLVE IT

Explanation / Answer

1)
initially capacitor acts as short ckt

Rnet = Ro + R1*R2/(R1+R2) = 33.2 ohm

I = v/Rnet = 0.06 A

current through R1, i1 = I*R2/(R1+R2) = 0.0388 A

2)current through R2, i2 = I*R1/(R1+R2) = 0.021 A


3)current through capacitor = current through R2 = I*R1/(R1+R2) = 0.021 A


4)
after a long time Capacitor acts as open ckt

Rnet = Ro+R1 = 38 ohm

current through R1,i = V/Rnet = 0.0526 A

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