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For full points I need to see the work and a correct answer. Thank you. a01 and

ID: 2123345 • Letter: F

Question

For full points I need to see the work and a correct answer.


Thank you.


a01 and a02. a point mass m moves in a circular path of constant radius r as shown in the diagram. Its position vector is = (rcos theta) + (r sin theta), where theta = radians, where alpha is a constant with units rad/sec 2 Using the vector definition of Torque , find an expression for the torque acting on the mass Use to find an expression for the angular momentum vector . Using , find an expression for the angular velocity vector .

Explanation / Answer

a) torque = r(costheta i + sintheta j) x (mg -k)

==> torque = mgr(costheta j - sintheta i ) = mgr(cos(alpha*t^2/2) j - sin(alpha*t^2/2) i )

b)dL/dt = torque = mgr d{(cos(alpha*t^2/2) j - sin(alpha*t^2/2)i )}/dt

==> L = mgr*alpha*t(sin(alpha*t^2/2) j - cos(alpha*t^2/2) i)

c)L = Iw = mr^2*w

d)|torque| = mgr sqrt(cos^2(alpha*t^2/2)+sin^2(alpha*t^2/2))

==>|torque| = mgr