2. A patient\'s plasma volume is 3L, and his plasma osmolarity is 280mOsM. The p

Question

2. A patient's plasma volume is 3L, and his plasma osmolarity is 280mOsM. The patient is given 1L of an intravenous solution that contains the following: 140mM NaCL · 90 mg/dL glucose . Urea, measured as 14mg/dL BUN. a. What is the osmolarity of the the NaCl in the IV solution? b. What is the osmolarity of the the glucose in the IV solution? c. BUN is blood urea nitrogen, a common laboratory measurement. BUN measures the mass of nitrogen from urea present in a volume of blood. Each urea molecule contains two nitrogens, and the molecular weight of nitrogen is 14g/mol. Use the molecular weight of nitrogen to determine the molarity of urea in the solution. What is the osmolarity of the urea in the IV solution? What is the total osmolarity of the IV solution? What is the new osmolarity of the patient's plasma after the IV solution is added to it? Assume that all of the IV solution ends up in the plasma, and not other compartments. d. e.

Explanation / Answer

a)The osmolarity of NaCl in IV solution is-

Molecular weifht of Nacl=140mM

1 mol of NaCl =1 mol of Na +1mol of Cl=2

=140mM/L X 2=280mOsM

b)Osmolarity of 90mg/dl glucose in IV solution

=90/18(molecular weight)

=5mOSM

c)Molarity of urea=14/14x2=14/28=0.5x10=5M

Osmolarity of urea in the IV solution

=14/2.8

=5mOSM

d)Total osmolarity of the IV solution=.280+5=285mOSM.

e)New Osmolarity of the plasma after the IV solution is added=280+5+5=290mOSM

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