If a slit diffracts 510 nm light so that the diffraction maximum is 7 cm class=\

Question

If a slit diffracts 510 nm light so that the diffraction maximum is 7 cmclass="mathjax_preview">style="border-left: 0em solid; display: inline-block; overflow: hidden; width: 0px; height: 0.741em; vertical-align: -0.091em;">style="display: inline-block; width: 0px; height: 2.224em;">style="font-family: mathjax_main;" id="mathjax-span-13" class="mi">style="font-family: mathjax_main;" id="mathjax-span-12" class="mi">id="mathjax-span-11" class="mrow">id="mathjax-span-10" class="texatom">id="mathjax-span-9" class="mrow">style="position: absolute; clip: rect(1.595em, 1000em, 2.415em, -0.507em); top: -2.224em; left: 0em;">style="display: inline-block; position: relative; width: 21px; height: 0px; font-size: 128%;">id="mathjax-span-8" class="math"> wide on a screen 2.9 m  away, what will be the width of the diffraction maximu for light with a wavelength of 450 nm?
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Explanation / Answer

we have

fringe width= 510*2.9/d

so 0.07=510*10^-9*2.9/d

or d= 2.11*10^-5 m

so when lambda is 450 nm

then frindge width

450/510*7 cm

= 6.176 cm

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