If a skin diver takes a breath at the surface, filling his lungs with 5.82 L of

Question

If a skin diver takes a breath at the surface, filling his lungs with 5.82 L of air, what volume will the air in his lungs occupy when he dives to a depth where the pressure is 1.92 atm. (Assume the surface is 1.00 atm) A sample of argon gas that originally occupied 14.6 L at 25.0 degree C was heated to 50.0 degree C at constant pressure. What is its new volume? If 3.0 L of NO are combined with 1.5 L of O_2 and they react according to the equation 2 NO + O_2 rightarrow 2 NO_2 what volume of NO_2 will be produced? If a child releases a 6.25 L balloon in the parking lot of an amusement park where the temperature is 28.50 degree C and an air pressure of 757.2 mmHg, what will the volume of the balloon be when it has risen to an altitude where the temperature is -34.35 degree C and the air pressure is 366.4 mmHg?

Explanation / Answer

Ans 1.

According to Boyle's law , pressure is inveresely related to the volume , and it is given as ,

p1V1 = p2V2

where p is pressure in atm and V is volume in L

putting all the values in the formula , we get ,

1.00 x 5.82 = 1.92 x V2

V2 = 3.03 L

So the air occupies volume 3.03L at 1.86 atm

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