Consider laser eye surgery, in which laser light with a wavelength of 510 nm at

Question

Consider laser eye surgery, in which laser light with a wavelength of 510 nm at a power output of 1.3 W is used to reattach a detached retina. Suppose the laser is pulsed for 0.058-s time intervals.

Consider laser eye surgery, in which laser light with a wavelength of 510 nm at a power output of 1.3 W is used to reattach a detached retina. Suppose the laser is pulsed for 0.058-s time intervals. During this time, how many photons are emitted by the laser? What is the difference in energy between the two energy levels involved in this laser transition?

Explanation / Answer

the energy difference is

E = (h x c/lamda)

where h = 6.63 x 10^-34 J-s,c = 3 x 10^8 m/s and lamda = 510 nm = 510 x 10^-9 m

we know that

1 eV = 1.6 x 10^-19 J

or 1 J = (1/1.6 x 10^-19) eV

the power of the laser light is

P = (E/t)

where t is time

the output power is

P_o = 1.5 W

the number of photons emitted is

n = (P_o/P)

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