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In the figure, two conducting balls of identical mass m = 10 g and identical cha

ID: 2125883 • Letter: I

Question

In the figure, two conducting balls of identical mass m = 10 g and identical charge q hang from nonconducting threads of length L = 120 cm. If x = 6.2 cm, what is q? Since x is much smaller than L approximate sin(?) by ?.




**PLEASE use the exact figures given in my problem, not different examples because I'm really lost here and I want to be able to follow it directly


Link to the exact figure needed below:


https://www.chegg.com/homework-help/questions-and-answers/figure-conducting-balls-identical-mass-m-10g-identical-charge-q-hang-nonconducting-threads-q1428488

Explanation / Answer

In the y direction, the forces are the weight and the vertical component of the Tension, so...

mg = Tcos(angle)

sin(angle) = 3.1/120

angle = 1.48 degrees

(.01)(9.8) = (T)(cos 1.48)

T = .098 N


In the x direction, the electrical force is balanced by the x component of the tension

kqq/r^2 = Tsin(angle)

(9 X 10^9)(q^2)/(.062)^2 = (.098)(sin 1.48)

q = 3.29 X 10^-8 C (which is 32.9 nC)

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