Type your question here In class we found the Bohr model predicts the distance b

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In class we found the Bohr model predicts the distance between the electron and proton in a hydrogen atom to be 0.529 A. Consider the ground state wavelength of the electron in orbit around the proton to be equal to the circumference of a circular orbit of radius 0.529 A. Use de Broglie's relationship lambda = h/p and the expression for kinetic energy in terms of momentum: E = p2/2m to calculate the energy of the de Broglie electron in its orbit around the hydrogen atom. Report the energy in both units of electron volts (eV) and kJ mole-1. Calculate the velocity of the electron in its orbit around the proton.

Explanation / Answer

wavelength = circumference

==> lamda = 2 pi R = 2*3.1416*0.529e-10 = 3.324e-10 m

lamda = h/p

==> p = h/lamda = 6.626e-34/3.324e-10 = 1.993e-24 Kg.m/s

E = p^2/2m = 1.993e-24*1.993e-24/(2*9.109e-31) = 2.18e-18 J = 2.18e-18/1.6e-19 eV = 13.6 eV

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