A single mass m 1 = 3.3 kg hangs from a spring in a motionless elevator. The spr

Question

A single mass m1 = 3.3 kg hangs from a spring in a motionless elevator.  The spring is extended x = 13 cm from its unstretched length.

Now, three masses m1 = 3.3 kg, m2 = 9.9 kg and m3 = 6.6 kg hang from three identical springs in a motionless   elevator.  The springs all have the same spring constant that you just calculated above. k =248.76

Now the elevator is moving downward with a velocity of v = -2 m/s but accelerating upward with an acceleration of a = 4.5 m/s2.  (Note: an upward acceleration when the elevator is moving down means the elevator is slowing down.)

Finally, the elevator is moving downward with a velocity of v = -3.8 m/s and also accelerating downward at an acceleration of a = -2.2 m/s2.

What is the distance the MIDDLE spring is extended from its unstretched length?

Explanation / Answer

F = kx = ma

x = ma/k = 9.9*(-2.2)/258.76

x = 0.08 m

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