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A 0.750 kg air-track glider is attached to each end of the track by two coil spr

ID: 2127697 • Letter: A

Question

A 0.750 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.900 N to displace the glider to a new equilibrium position, x= 0.070 m.


Find the effective spring constant of the system.
Answer: 1.29?101N/m


The glider is now released from rest at x= 0.070 m. Find the maximum x-acceleration of the glider.
Answer:
1.20 m/s^2


I need help with this two!


Find the x-coordinate of the glider at time t= 0.450T, where T is the period of the oscillation.


Find the kinetic energy of the glider at x=0.00 m.



Please show work, THANKS!

Explanation / Answer

=sqrt(k/m)=4.15

The equation of motion for mass=ACost

Putting t=0.45T=0.9/,

x=-0.0666m

Kinetic energy at cente=0.5kA2=0.0316J