A 0.750 kg air-track glider is attached to each end of the track by two coil spr
ID: 2127697 • Letter: A
Question
A 0.750 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.900 N to displace the glider to a new equilibrium position, x= 0.070 m.
Find the effective spring constant of the system.
Answer: 1.29?101N/m
The glider is now released from rest at x= 0.070 m. Find the maximum x-acceleration of the glider.
Answer:1.20 m/s^2
I need help with this two!
Find the x-coordinate of the glider at time t= 0.450T, where T is the period of the oscillation.
Find the kinetic energy of the glider at x=0.00 m.
Please show work, THANKS!
Explanation / Answer
=sqrt(k/m)=4.15
The equation of motion for mass=ACost
Putting t=0.45T=0.9/,
x=-0.0666m
Kinetic energy at cente=0.5kA2=0.0316J
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