A 0.65-m aluminum bar is held with its length parallel to the east-west directio

Question

A 0.65-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar hits the river below, its speed is 24 m/s, and the emf induced across its length is 5.8 x 10-4 V. Assuming the horizontal component of the Earth's magnetic field at the location of the bar points directly north, (a) determine the magnitude of the horizontal component of the Earth's magnetic field, and (b) state the number of which end of the bar is positive: 1 = east, 2 = west.

Explanation / Answer

The formula for induced EMF on a wire is...

= BLv

So B = /Lv

B = (5.8 X 10-4)/(.64)(24)

B = 8.91 X 10-3 T and the East side (by the right hand rule) is positive; so the anser to part B is 1

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