A 0.650 kg air-track glider is attached to each end of the track by two coil spr
ID: 1312840 • Letter: A
Question
A 0.650 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the qlider to a new equilibrium position, x= 0.210 m. Find the effective spring constant of the system. 3.33 N/m The qlider is now released from rest at x= 0.210 m. Find the maximum x-acceleration of the glider. 1.08 m/s 2 Find the glider at time t= 0.350T, where T is the period of the oscillation. Find the kinetic energy of the glider at x=0.00 m. Use conservation of energyExplanation / Answer
x=0.21 cos(w*t)
w=(k/m)^0.5
m=0.65 k=3.33
w=2.263 T=2.776sec
using energy conversion: KE of body=PE of spring
1/2(k)(x^2)=1/2(m)(v^2)
v=0.4753m/s
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