A Flower Pot Falling Past a Window As you look out of your dorm window, a flower
ID: 2128603 • Letter: A
Question
A Flower Pot Falling Past a Window As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that doenward velocities are positive and the acceleration due to gravity is the positive quantity g. Assume that the flower was dropped by someone on the floor above you (rather than thrown downward).Part A From what height h above the bottom of your window was the flower pot dropped? Express your answer in terms of Lw, t, and g. h = Lw2/2gt2 + gt2/8 + Lw/2 Part B If the bottom of your window is a height hb above the ground, what is the velocity vground of the pot as it hits the ground the new variable vb, the speed at the bottom of the window, defined by vb = Lw/t + gt/2. Express your answer in terms of some or all of the variables hb, Lw, t, vb, and g.Explanation / Answer
we can use that v^2 = v0^2 + 2 a x
so v ground ^2 = vb^2 - 2*g*-h
v ground = sqrt( vb^2 + 2 g h)
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