Two resistors, 46.0 ? and 30.0 ? , are connected in parallel. The current throug

Question

Two resistors, 46.0 ? and 30.0 ?, are connected in parallel. The current through the second resistor is 3.10 A.

Two resistors, 46.0 ? and 30.0 ?, are connected in parallel. The current through the second resistor is 3.10 A. Determine the current in the first resistor? What is the total power supplied to the two resistors? Consider the circuit in the drawing. (R1 = 6.0 ?, R2 = 24 ?, V1 = 35.0 V.) Determine the magnitude of the current in the circuit. Determine the magnitude of the voltage between the points labeled A and B. Select which point, A or B, is at the higher potential. Two capacitors are connected in parallel across the terminals of a battery. One has a capacitance of 2.0 muF and the other a capacitance of 5.0 muF. These two capacitors together store 5.40 times 10-5 C of charge. What is the voltage of the battery?

Explanation / Answer

a) I = 3.1 x 30 /46 = 2.02

b) Power supplied = 2.02^2 x 46 + 3.1^2 x 30 = 476 W

2) a ) -10 - 50 I + 35 = 0

I = 0.5 A

b) Va +35 - 24 x 0.5 = Vb

Vab = 12 - 35 = -23 V

c) B is at highr potential

3) V = Q/(c1+c2) = 5.4 x 10^-5 /(2x10^-6 + 5 x 10^-6 ) = 7.71 V

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