Must show work. Explanation so i can follow work. Two small frogs simultaneously

Question

                    Must show work. Explanation so i can follow work.
                

                

                    
                

                

                                          

Two small frogs simultaneously leap straight up from a lily pad. Frog A leaps with an initial velocity of 0.901 m/s, while frog B leaps with an initial velocity of 1.75 m/s. When the first frog to return to the lily pad does so, what is the position and velocity of the other frog? Take upwards to be positive, and let the position of the lily pad be zero. Position: Velocity:

Explanation / Answer

The time for frog A can be calculated from vf = vo + at

-0.901 = 0.901 * (9.8)t--------> t= 0.1838 s

Now we will use that time for frog B vf = vo + at

vf = 1.75 + (-9.8)(0.1838)-------> Vf =0.05124 m/s   (Note its positive)

For the displacement, d = vot + .5at^2

d = (1.75)(0.1838) + (.5)(-9.8)(0.1838)^2

d = 0. 1523 m

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