One ml of the unknowns carbohydrate is combined with 5.0 ml of Benedict\'s reage
ID: 213074 • Letter: O
Question
One ml of the unknowns carbohydrate is combined with 5.0 ml of Benedict's reagent in large tes inisat he tube are mixed and heated in a boiling water bath for 5 minutes. Greenish red precipitation indicates a positive test T ransfer 5 drops of the unknown carbohydrate in small test tubes and add two drops of lodine-I solution. The immediate formation of a vivid blue color indicates amylose or starch. 12.1.7 Data analysis of Unknown Set # Resorcino Benedicts Molisch Test Test Test Test Solution A Solution B | - | ellow Solution C Solution D Solution E RED Solution F reen Such) oran cear Ptir K Indicate the sugar in six unknown solution and justify your answer SolutionA: Solutlon B: Solutlon C: Solution D: Solutlon E: Solution F:Explanation / Answer
Solution A contains a reducing sugar having ketone as the functional group that gets reduce to give red color. The reducing sugar in this case can be either a monosaccharide or a disaccharide.
Solution B contains starch solution as it is able to give Blue black color as ar result of addition of triiodide.
Solution C contains a reducing disaccharide sugar with aldehyde as the functional group present because it is able to give both Benedict and Molisch test. Solution D contains no carbohydrate molecules as it does not give any positive results for any of these tests.
Solution E contains a non reducing monosaccharide sugar which has ketone group present as the functional group because it is able to give only Molisch test.
Solution F contains a reducing disaccharide sugar which has aldehyde as the functional group present in it because it can give both Molisch and Benedict test.
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