A popular circus act feature daredevil motorcycle riders encased in the \" Globe

Question

A popular circus act feature daredevil motorcycle riders encased in the " Globe of Death"( see the figure below), a spherical metal cage of diameter 17 ft. Assume a speed of 22mi/h fof both tricks. A rider of mass 64 kg on a 125 - cc ( 95-kg) motorcycle keeps his bike horizontal as he rides around the " equator" of the globe. What coefficient of friction is needed between his tire and the cage to keep him in place? How many loops will the rider make per second ? e same rider performs vertical loops in the globe. What force does the cage need to withstand at the top and the bottom of the rider's loop ?

Explanation / Answer

A) for biker to be in horizontal position

friction force = mg

(mu)N = mg and N = cenrigugal force = mv^2/r

(mu)mv^2/r = mg

(mu) = gr/v^2 = 9.8 x 2.5908 /(9.835^2) = 0.26

coefficient of friction = 0.26

B) v = wr

w = 3.796 rad/s

0.605 loops per second

C)Ftop = mv^2/r - mg = 4378.047 N

Fbottom = mv^2/r + mg= 7494.45 N

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