a. Rearrange Equation 5 solved for I to match y = mx + b. b. What is the experim

Question

a. Rearrange Equation 5 solved for I to

match y = mx + b.

b. What is the experimental potential

difference?

c. Calculate the percent difference from the

15.0 V that the experimenter set on the

power supply (the instrument used for

such experiments).

d. Comment on the experimental intercept:

is its value reasonable?

This graph (Fig. 5) also follows Ohm's Law, but solved for current I. For this graph the experimenter held potential difference AV constant at 15.0V and measured the current for resistances of 100, 50, 40, and 30Ohm. Solve Ohm's Law for I and you will see that 1/R is the logical variable to use on the x axis. For units, someone once jokingly referred to a "reciprocal ohm" as a "ohm" and the name stuck. Rearrange Equation 5 solved for I to match y = mx + b. What is the experimental potential difference? Calculate the percent difference from the 15.0 V that the experimenter set on the power supply (the instrument used for such experiments). Comment on the experimental intercept: is its value reasonable?

Explanation / Answer

a) I = 14.72*(r^-1) + 0.2214

b)Experimental potential difference = 14.72 v

c)1.82% [(15-14.72)/15 * 100 ]

d)It could be due to non-ideality of the source. The resistance of the source is coupled with the actual resistors. It is a reasonable value because a potential of 0.38v across the source is acceptable.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.