Use the step-by-step method below to solve this problem Problem Step-by-step met
ID: 2133496 • Letter: U
Question
Use the step-by-step method below to solve this problem
Problem
Step-by-step method to follow:
Explanation / Answer
sol)
1)let the impdance of capcitor = Z1 = 1/jwC
and the impedance of resistor = Z2 = R
by using voltage division rule
we can find
step 1)
V0= Vin*Z2/(Z1+Z2)
substituting Z1 and Z2
V0/Vin = R /(1/jwC+R) = jwRC/(1+jwRC)
step 2) magnitude = sqrt(real^2+img^2)/sqrt(real^2+img^2)
= sqrt(0^2+jwRC^2)/sqrt(1^2+jRC^2)
|Vout/Vin |= wRC/sqrt(1+(wRC)^2))
arg (vout/vin) = tan inverse (wrc/0) - tan inverse(wRC/1)
= 90 - tan invers (wRC)
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