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Model the eye as a single lens, n=1.4, air in front of it and fluid (n=1.3) behi

ID: 2134628 • Letter: M

Question

Model the eye as a single lens, n=1.4, air in front of it and fluid (n=1.3) behind it. The eyball is spherical with a diameter of 2.5 cm. The front of the eye has the same curvature as the eyeball. The lens power is 52D.

1). 20cm from the eye you can see your image right way up.

a) What is the vergence of the light from your face as it is about to strike the eyeball?

b) What is the reflective power of the surface of the eyeball?

c) Is the reflective image real or virtual.

d) What is the image location and magnification of the reflected image.


2. A laser produces a spot of red light, lambda is 650nm and the laser output is 1.5 mW. 1 mW=1mJ/s.

a) Use a ray diagram and calculate what would happen if the laser entered the eye described previously.

b) This would cause the person to blink from the laser light .20 plus or minus .06 seconds. Calculate including the uncertainty how many photons would enter the eye before it closed.

c) The Maximum Permissible Exposure is the concentration of energy safe for the eye, here it is 32 J m^2 on the front of the eye. With an even 1.8 mm beam on the eye surface is this safe, explain why or why not.

3. A 1cm diameter glass  lens has the shape in the diagram and a refractive index of 1.46. It forms an image of an object 1 meter from the lens in air.



Use vergence to answer:

a) What is the lens power in air?

b) Where would the image be?

c) Is the image real or virtual, upright or inverted, larger or smaller than the object.

4. An opaque mask with a 1.0 cm diameter hole is between a screen and 2 lights as shown in the diagram. The two light form the figure 8 shape on the top of the diagram.




a) If the hole in the mask is gradually decreased do the circular patterns always remain separate from each other? Explain why.

Model the eye as a single lens, n=1.4, air in front of it and fluid (n=1.3) behind it. The eyball is spherical with a diameter of 2.5 cm. The front of the eye has the same curvature as the eyeball. The lens power is 52D. 20cm from the eye you can see your image right way up. What is the vergence of the light from your face as it is about to strike the eyeball? What is the reflective power of the surface of the eyeball? Is the reflective image real or virtual. What is the image location and magnification of the reflected image. A laser produces a spot of red light, lambda is 650nm and the laser output is 1.5 mW. 1 mW=1mJ/s. Use a ray diagram and calculate what would happen if the laser entered the eye described previously. This would cause the person to blink from the laser light .20 plus or minus .06 seconds. Calculate including the uncertainty how many photons would enter the eye before it closed. The Maximum Permissible Exposure is the concentration of energy safe for the eye, here it is 32 J m^2 on the front of the eye. With an even 1.8 mm beam on the eye surface is this safe, explain why or why not. A 1cm diameter glass lens has the shape in the diagram and a refractive index of 1.46. It forms an image of an object 1 meter from the lens in air.

Explanation / Answer

PHYS1002 Problem Set 3, am looking for the same thing :D

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