Parallel plate capacitor #1 has plate area A , separation distance d , and capac
ID: 2135060 • Letter: P
Question
Parallel plate capacitor #1 has plate area A, separation distance d, and capacitance C1. Parallel plate capacitor #2 is made by starting with capacitor #1 and adding a dielectric with k = 2 of thickness d/2 that covers half the area Adielectric = (1/2)A. What is the capacitance C2 of capacitor #2 in terms of C1.
I need an explanation of how to get the answer, I'm stuck. I know to split C2 into 2 parallel capacitors, but what do I do since the dielectric's width is only 1/2d?
Parallel plate capacitor #1 has plate area A, separation distance d, and capacitance C1. Parallel plate capacitor #2 is made by starting with capacitor #1 and adding a dielectric with k = 2 of thickness d/2 that covers half the area Adielectric = (1/2)A. What is the capacitance C2 of capacitor #2 in terms of C1.Explanation / Answer
we can treat the second capacitor as a combination of 3 capacitors...
C2 = c1/2 + c1*2*c1/(c1+2c1)
= c1/2 + (2/3)*c1
= (3*c1 + 4*c1 )/ 6
= (7/6)*c1
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